9(2x+3)^2-25(2x+3)+16=0

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Solution for 9(2x+3)^2-25(2x+3)+16=0 equation:



9(2x+3)^2-25(2x+3)+16=0
We multiply parentheses
9(2x+3)^2-50x-75+16=0
We add all the numbers together, and all the variables
-50x+9(2x+3)^2-59=0
We move all terms containing x to the left, all other terms to the right
-50x+9(2x+3)^2=59

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